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Solution - Absolute value equations

Exact form: n=5
n=5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|n8||n+2|=0

Add |n+2| to both sides of the equation:

|n8||n+2|+|n+2|=|n+2|

Simplify the arithmetic

|n8|=|n+2|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|n8|=|n+2|
without the absolute value bars:

|x|=|y||n8|=|n+2|
x=+y(n8)=(n+2)
x=y(n8)=((n+2))
+x=y(n8)=(n+2)
x=y(n8)=(n+2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||n8|=|n+2|
x=+y , +x=y(n8)=(n+2)
x=y , x=y(n8)=((n+2))

3. Solve the two equations for n

11 additional steps

(n-8)=(-n+2)

Add to both sides:

(n-8)+n=(-n+2)+n

Group like terms:

(n+n)-8=(-n+2)+n

Simplify the arithmetic:

2n-8=(-n+2)+n

Group like terms:

2n-8=(-n+n)+2

Simplify the arithmetic:

2n8=2

Add to both sides:

(2n-8)+8=2+8

Simplify the arithmetic:

2n=2+8

Simplify the arithmetic:

2n=10

Divide both sides by :

(2n)2=102

Simplify the fraction:

n=102

Find the greatest common factor of the numerator and denominator:

n=(5·2)(1·2)

Factor out and cancel the greatest common factor:

n=5

6 additional steps

(n-8)=-(-n+2)

Expand the parentheses:

(n-8)=n-2

Subtract from both sides:

(n-8)-n=(n-2)-n

Group like terms:

(n-n)-8=(n-2)-n

Simplify the arithmetic:

-8=(n-2)-n

Group like terms:

-8=(n-n)-2

Simplify the arithmetic:

8=2

The statement is false:

8=2

The equation is false so it has no solution.

4. List the solutions

n=5
(1 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|n8|
y=|n+2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.