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Solution - Absolute value equations

Exact form: x=1112
x=\frac{11}{12}
Mixed number form:
Decimal form: x=0.917
x=0.917

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|x+56|-|x-83|=0

Add |x-83| to both sides of the equation:

|x+56|-|x-83|+|x-83|=|x-83|

Simplify the arithmetic

|x+56|=|x-83|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x+56|=|x-83|
without the absolute value bars:

|x|=|y||x+56|=|x-83|
x=+y(x+56)=(x-83)
x=-y(x+56)=(-(x-83))
+x=y(x+56)=(x-83)
-x=y-(x+56)=(x-83)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x+56|=|x-83|
x=+y , +x=y(x+56)=(x-83)
x=-y , -x=y(x+56)=(-(x-83))

3. Solve the two equations for x

5 additional steps

(x+56)=(x+-83)

Subtract from both sides:

(x+56)-x=(x+-83)-x

Group like terms:

(x-x)+56=(x+-83)-x

Simplify the arithmetic:

56=(x+-83)-x

Group like terms:

56=(x-x)+-83

Simplify the arithmetic:

56=-83

The statement is false:

56=-83

The equation is false so it has no solution.

19 additional steps

(x+56)=-(x+-83)

Expand the parentheses:

(x+56)=-x+83

Add to both sides:

(x+56)+x=(-x+83)+x

Group like terms:

(x+x)+56=(-x+83)+x

Simplify the arithmetic:

2x+56=(-x+83)+x

Group like terms:

2x+56=(-x+x)+83

Simplify the arithmetic:

2x+56=83

Subtract from both sides:

(2x+56)-56=(83)-56

Combine the fractions:

2x+(5-5)6=(83)-56

Combine the numerators:

2x+06=(83)-56

Reduce the zero numerator:

2x+0=(83)-56

Simplify the arithmetic:

2x=(83)-56

Find the lowest common denominator:

2x=(8·2)(3·2)+-56

Multiply the denominators:

2x=(8·2)6+-56

Multiply the numerators:

2x=166+-56

Combine the fractions:

2x=(16-5)6

Combine the numerators:

2x=116

Divide both sides by :

(2x)2=(116)2

Simplify the fraction:

x=(116)2

Simplify the arithmetic:

x=11(6·2)

x=1112

4. Graph

Each line represents the function of one side of the equation:
y=|x+56|
y=|x-83|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.