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Solution - Absolute value equations

Exact form: x=5,73
x=5 , \frac{7}{3}
Mixed number form: x=5,213
x=5 , 2\frac{1}{3}
Decimal form: x=5,2.333
x=5 , 2.333

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x1|=2|x3|
without the absolute value bars:

|x|=|y||x1|=2|x3|
x=+y(x1)=2(x3)
x=y(x1)=2((x3))
+x=y(x1)=2(x3)
x=y(x1)=2(x3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x1|=2|x3|
x=+y , +x=y(x1)=2(x3)
x=y , x=y(x1)=2((x3))

2. Solve the two equations for x

12 additional steps

(x-1)=2·(x-3)

Expand the parentheses:

(x-1)=2x+2·-3

Simplify the arithmetic:

(x-1)=2x-6

Subtract from both sides:

(x-1)-2x=(2x-6)-2x

Group like terms:

(x-2x)-1=(2x-6)-2x

Simplify the arithmetic:

-x-1=(2x-6)-2x

Group like terms:

-x-1=(2x-2x)-6

Simplify the arithmetic:

x1=6

Add to both sides:

(-x-1)+1=-6+1

Simplify the arithmetic:

x=6+1

Simplify the arithmetic:

x=5

Multiply both sides by :

-x·-1=-5·-1

Remove the one(s):

x=-5·-1

Simplify the arithmetic:

x=5

14 additional steps

(x-1)=2·(-(x-3))

Expand the parentheses:

(x-1)=2·(-x+3)

(x-1)=2·-x+2·3

Group like terms:

(x-1)=(2·-1)x+2·3

Multiply the coefficients:

(x-1)=-2x+2·3

Simplify the arithmetic:

(x-1)=-2x+6

Add to both sides:

(x-1)+2x=(-2x+6)+2x

Group like terms:

(x+2x)-1=(-2x+6)+2x

Simplify the arithmetic:

3x-1=(-2x+6)+2x

Group like terms:

3x-1=(-2x+2x)+6

Simplify the arithmetic:

3x1=6

Add to both sides:

(3x-1)+1=6+1

Simplify the arithmetic:

3x=6+1

Simplify the arithmetic:

3x=7

Divide both sides by :

(3x)3=73

Simplify the fraction:

x=73

3. List the solutions

x=5,73
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|x1|
y=2|x3|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.