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Solution - Absolute value equations

Exact form: x=192
x=\frac{19}{2}
Mixed number form: x=912
x=9\frac{1}{2}
Decimal form: x=9.5
x=9.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|x5|+|x14|=0

Add |x14| to both sides of the equation:

|x5|+|x14||x14|=|x14|

Simplify the arithmetic

|x5|=|x14|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x5|=|x14|
without the absolute value bars:

|x|=|y||x5|=|x14|
x=+y(x5)=(x14)
x=y(x5)=(x14)
+x=y(x5)=(x14)
x=y(x5)=(x14)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x5|=|x14|
x=+y , +x=y(x5)=(x14)
x=y , x=y(x5)=(x14)

3. Solve the two equations for x

10 additional steps

(x-5)=-(x-14)

Expand the parentheses:

(x-5)=-x+14

Add to both sides:

(x-5)+x=(-x+14)+x

Group like terms:

(x+x)-5=(-x+14)+x

Simplify the arithmetic:

2x-5=(-x+14)+x

Group like terms:

2x-5=(-x+x)+14

Simplify the arithmetic:

2x5=14

Add to both sides:

(2x-5)+5=14+5

Simplify the arithmetic:

2x=14+5

Simplify the arithmetic:

2x=19

Divide both sides by :

(2x)2=192

Simplify the fraction:

x=192

6 additional steps

(x-5)=-(-(x-14))

NT_MSLUS_MAINSTEP_RESOLVE_DOUBLE_MINUS:

(x-5)=x-14

Subtract from both sides:

(x-5)-x=(x-14)-x

Group like terms:

(x-x)-5=(x-14)-x

Simplify the arithmetic:

-5=(x-14)-x

Group like terms:

-5=(x-x)-14

Simplify the arithmetic:

5=14

The statement is false:

5=14

The equation is false so it has no solution.

4. List the solutions

x=192
(1 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|x5|
y=|x14|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.