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Solution - Absolute value equations

Exact form: y=-1,-32
y=-1 , -\frac{3}{2}
Mixed number form: y=-1,-112
y=-1 , -1\frac{1}{2}
Decimal form: y=1,1.5
y=-1 , -1.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|y+2|=|3y+4|
without the absolute value bars:

|x|=|y||y+2|=|3y+4|
x=+y(y+2)=(3y+4)
x=y(y+2)=(3y+4)
+x=y(y+2)=(3y+4)
x=y(y+2)=(3y+4)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||y+2|=|3y+4|
x=+y , +x=y(y+2)=(3y+4)
x=y , x=y(y+2)=(3y+4)

2. Solve the two equations for y

12 additional steps

(y+2)=(3y+4)

Subtract from both sides:

(y+2)-3y=(3y+4)-3y

Group like terms:

(y-3y)+2=(3y+4)-3y

Simplify the arithmetic:

-2y+2=(3y+4)-3y

Group like terms:

-2y+2=(3y-3y)+4

Simplify the arithmetic:

2y+2=4

Subtract from both sides:

(-2y+2)-2=4-2

Simplify the arithmetic:

2y=42

Simplify the arithmetic:

2y=2

Divide both sides by :

(-2y)-2=2-2

Cancel out the negatives:

2y2=2-2

Simplify the fraction:

y=2-2

Move the negative sign from the denominator to the numerator:

y=-22

Simplify the fraction:

y=1

12 additional steps

(y+2)=-(3y+4)

Expand the parentheses:

(y+2)=-3y-4

Add to both sides:

(y+2)+3y=(-3y-4)+3y

Group like terms:

(y+3y)+2=(-3y-4)+3y

Simplify the arithmetic:

4y+2=(-3y-4)+3y

Group like terms:

4y+2=(-3y+3y)-4

Simplify the arithmetic:

4y+2=4

Subtract from both sides:

(4y+2)-2=-4-2

Simplify the arithmetic:

4y=42

Simplify the arithmetic:

4y=6

Divide both sides by :

(4y)4=-64

Simplify the fraction:

y=-64

Find the greatest common factor of the numerator and denominator:

y=(-3·2)(2·2)

Factor out and cancel the greatest common factor:

y=-32

3. List the solutions

y=-1,-32
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|y+2|
y=|3y+4|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.