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Solution - Absolute value equations

Exact form: x=13,3
x=\frac{1}{3} , 3
Decimal form: x=0.333,3
x=0.333 , 3

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

2|x1|+|x+1|=0

Add |x+1| to both sides of the equation:

2|x1|+|x+1||x+1|=|x+1|

Simplify the arithmetic

2|x1|=|x+1|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
2|x1|=|x+1|
without the absolute value bars:

|x|=|y|2|x1|=|x+1|
x=+y2(x1)=(x+1)
x=y2(x1)=(x+1)
+x=y2(x1)=(x+1)
x=y2((x1))=(x+1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y|2|x1|=|x+1|
x=+y , +x=y2(x1)=(x+1)
x=y , x=y2(x1)=(x+1)

3. Solve the two equations for x

12 additional steps

2·(x-1)=-(x+1)

Expand the parentheses:

2x+2·-1=-(x+1)

Simplify the arithmetic:

2x-2=-(x+1)

Expand the parentheses:

2x2=x1

Add to both sides:

(2x-2)+x=(-x-1)+x

Group like terms:

(2x+x)-2=(-x-1)+x

Simplify the arithmetic:

3x-2=(-x-1)+x

Group like terms:

3x-2=(-x+x)-1

Simplify the arithmetic:

3x2=1

Add to both sides:

(3x-2)+2=-1+2

Simplify the arithmetic:

3x=1+2

Simplify the arithmetic:

3x=1

Divide both sides by :

(3x)3=13

Simplify the fraction:

x=13

10 additional steps

2·(x-1)=-(-(x+1))

Expand the parentheses:

2x+2·-1=-(-(x+1))

Simplify the arithmetic:

2x-2=-(-(x+1))

Resolve the double minus:

2x2=x+1

Subtract from both sides:

(2x-2)-x=(x+1)-x

Group like terms:

(2x-x)-2=(x+1)-x

Simplify the arithmetic:

x-2=(x+1)-x

Group like terms:

x-2=(x-x)+1

Simplify the arithmetic:

x2=1

Add to both sides:

(x-2)+2=1+2

Simplify the arithmetic:

x=1+2

Simplify the arithmetic:

x=3

4. List the solutions

x=13,3
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=2|x1|
y=|x+1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.