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Solution - Absolute value equations

Exact form: x=-12,-52
x=-\frac{1}{2} , -\frac{5}{2}
Mixed number form: x=-12,-212
x=-\frac{1}{2} , -2\frac{1}{2}
Decimal form: x=0.5,2.5
x=-0.5 , -2.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
4|x+2|=|2x+7|
without the absolute value bars:

|x|=|y|4|x+2|=|2x+7|
x=+y4(x+2)=(2x+7)
x=y4(x+2)=(2x+7)
+x=y4(x+2)=(2x+7)
x=y4((x+2))=(2x+7)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y|4|x+2|=|2x+7|
x=+y , +x=y4(x+2)=(2x+7)
x=y , x=y4(x+2)=(2x+7)

2. Solve the two equations for x

11 additional steps

4·(x+2)=(2x+7)

Expand the parentheses:

4x+4·2=(2x+7)

Simplify the arithmetic:

4x+8=(2x+7)

Subtract from both sides:

(4x+8)-2x=(2x+7)-2x

Group like terms:

(4x-2x)+8=(2x+7)-2x

Simplify the arithmetic:

2x+8=(2x+7)-2x

Group like terms:

2x+8=(2x-2x)+7

Simplify the arithmetic:

2x+8=7

Subtract from both sides:

(2x+8)-8=7-8

Simplify the arithmetic:

2x=78

Simplify the arithmetic:

2x=1

Divide both sides by :

(2x)2=-12

Simplify the fraction:

x=-12

14 additional steps

4·(x+2)=-(2x+7)

Expand the parentheses:

4x+4·2=-(2x+7)

Simplify the arithmetic:

4x+8=-(2x+7)

Expand the parentheses:

4x+8=2x7

Add to both sides:

(4x+8)+2x=(-2x-7)+2x

Group like terms:

(4x+2x)+8=(-2x-7)+2x

Simplify the arithmetic:

6x+8=(-2x-7)+2x

Group like terms:

6x+8=(-2x+2x)-7

Simplify the arithmetic:

6x+8=7

Subtract from both sides:

(6x+8)-8=-7-8

Simplify the arithmetic:

6x=78

Simplify the arithmetic:

6x=15

Divide both sides by :

(6x)6=-156

Simplify the fraction:

x=-156

Find the greatest common factor of the numerator and denominator:

x=(-5·3)(2·3)

Factor out and cancel the greatest common factor:

x=-52

3. List the solutions

x=-12,-52
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=4|x+2|
y=|2x+7|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.