Solution - Long multiplication

Start by multiplying the ones digit (7) of the multiplier 5,657 by each digit of the multiplicand 42, from right to left.

Multiply the ones digit (7) of the multiplicator by the number in the ones place value:
7×2=14

Write 4 in the ones place.

Because the result is greater than 9, carry the 1 to the tens place.

Multiply the ones digit (7) of the multiplicator by the number in the tens place value and add the carried number (1):
7×4+1=29

Write 9 in the tens place.

Because the result is greater than 9, carry the 2 to the hundreds place.

294 is the first partial product.

Proceed by multiplying the tens digit (5) of the multiplier (5,657) by each digit of the multiplicand (42), from right to left.

Because digit (5) is in tens place, we shift partial result by 1 place(s) by placing 1 zero(s).

Multiply the tens digit (5) of the multiplicator by the number in the ones place value:
5×2=10

Write 0 in the tens place.

Because the result is greater than 9, carry the 1 to the hundreds place.

Multiply the tens digit (5) of the multiplicator by the number in the tens place value and add the carried number (1):
5×4+1=21

Write 1 in the hundreds place.

Because the result is greater than 9, carry the 2 to the thousands place.

2,100 is the second partial product.

Proceed by multiplying the hundreds digit (6) of the multiplier (5,657) by each digit of the multiplicand (42), from right to left.

Because digit (6) is in hundreds place, we shift partial result by 2 place(s) by placing 2 zero(s).

Multiply the hundreds digit (6) of the multiplicator by the number in the ones place value:
6×2=12

Write 2 in the hundreds place.

Because the result is greater than 9, carry the 1 to the thousands place.

Multiply the hundreds digit (6) of the multiplicator by the number in the tens place value and add the carried number (1):
6×4+1=25

Write 5 in the thousands place.

Because the result is greater than 9, carry the 2 to the ten thousands place.

25,200 is the third partial product.

Proceed by multiplying the thousands digit (5) of the multiplier (5,657) by each digit of the multiplicand (42), from right to left.

Because digit (5) is in thousands place, we shift partial result by 3 place(s) by placing 3 zero(s).

Multiply the thousands digit (5) of the multiplicator by the number in the ones place value:
5×2=10

Write 0 in the thousands place.

Because the result is greater than 9, carry the 1 to the ten thousands place.

Multiply the thousands digit (5) of the multiplicator by the number in the tens place value and add the carried number (1):
5×4+1=21

Write 1 in the ten thousands place.

Because the result is greater than 9, carry the 2 to the hundred thousands place.

210,000 is the fourth partial product.

294+2100+25200+210000=237594 long addition steps can be seen here

Because we have 6 digit(s) to the right of the decimal point in the numbers that are being multiplied, we move the decimal point 6 time(s) to the left (reducing the result by the factor of 1,000,000) to get the final result:

The solution is: 0.237594