Solution - Long multiplication
Step-by-step explanation
1. Rewrite the numbers from top to bottom aligned to the right
| Place value | ten thousands | thousands | hundreds | tens | ones |
| 2 | 5 | ||||
| × | 1 | 0 | 9 | 4 | |
2. Multiply the numbers using long multiplication method
Start by multiplying the ones digit (4) of the multiplier 1,094 by each digit of the multiplicand 25, from right to left.
Multiply the ones digit (4) of the multiplicator by the number in the ones place value:
4×5=20
Write 0 in the ones place.
Because the result is greater than 9, carry the 2 to the tens place.
| Place value | ten thousands | thousands | hundreds | tens | ones |
| 2 | |||||
| 2 | 5 | ||||
| × | 1 | 0 | 9 | 4 | |
| 0 | |||||
Multiply the ones digit (4) of the multiplicator by the number in the tens place value and add the carried number (2):
4×2+2=10
Write 0 in the tens place.
Because the result is greater than 9, carry the 1 to the hundreds place.
| Place value | ten thousands | thousands | hundreds | tens | ones |
| 1 | 2 | ||||
| 2 | 5 | ||||
| × | 1 | 0 | 9 | 4 | |
| 1 | 0 | 0 | |||
100 is the first partial product.
Proceed by multiplying the tens digit (9) of the multiplier (1,094) by each digit of the multiplicand (25), from right to left.
Because digit (9) is in tens place, we shift partial result by 1 place(s) by placing 1 zero(s).
| Place value | ten thousands | thousands | hundreds | tens | ones |
| 2 | 5 | ||||
| × | 1 | 0 | 9 | 4 | |
| 1 | 0 | 0 | |||
| 0 | |||||
Multiply the tens digit (9) of the multiplicator by the number in the ones place value:
9×5=45
Write 5 in the tens place.
Because the result is greater than 9, carry the 4 to the hundreds place.
| Place value | ten thousands | thousands | hundreds | tens | ones |
| 4 | |||||
| 2 | 5 | ||||
| × | 1 | 0 | 9 | 4 | |
| 1 | 0 | 0 | |||
| 5 | 0 | ||||
Multiply the tens digit (9) of the multiplicator by the number in the tens place value and add the carried number (4):
9×2+4=22
Write 2 in the hundreds place.
Because the result is greater than 9, carry the 2 to the thousands place.
| Place value | ten thousands | thousands | hundreds | tens | ones |
| 2 | 4 | ||||
| 2 | 5 | ||||
| × | 1 | 0 | 9 | 4 | |
| 1 | 0 | 0 | |||
| 2 | 2 | 5 | 0 | ||
2,250 is the second partial product.
Because the hundreds digit of the multiplicator equals 0, skip to the next digit.
Proceed by multiplying the thousands digit (1) of the multiplier (1,094) by each digit of the multiplicand (25), from right to left.
Because digit (1) is in thousands place, we shift partial result by 3 place(s) by placing 3 zero(s).
| Place value | ten thousands | thousands | hundreds | tens | ones |
| 2 | 5 | ||||
| × | 1 | 0 | 9 | 4 | |
| 1 | 0 | 0 | |||
| 2 | 2 | 5 | 0 | ||
| 0 | 0 | 0 |
Multiply the thousands digit (1) of the multiplicator by the number in the ones place value:
1×5=5
Write 5 in the thousands place.
| Place value | ten thousands | thousands | hundreds | tens | ones |
| 2 | 5 | ||||
| × | 1 | 0 | 9 | 4 | |
| 1 | 0 | 0 | |||
| 2 | 2 | 5 | 0 | ||
| 5 | 0 | 0 | 0 |
Multiply the thousands digit (1) of the multiplicator by the number in the tens place value:
1×2=2
Write 2 in the ten thousands place.
| Place value | ten thousands | thousands | hundreds | tens | ones |
| 2 | 5 | ||||
| × | 1 | 0 | 9 | 4 | |
| 1 | 0 | 0 | |||
| 2 | 2 | 5 | 0 | ||
| 2 | 5 | 0 | 0 | 0 |
25,000 is the third partial product.
3. Add the partial products
100+2250+25000=27350 long addition steps can be seen here
| Place value | ten thousands | thousands | hundreds | tens | ones |
| 2 | 5 | ||||
| × | 1 | 0 | 9 | 4 | |
| 1 | 0 | 0 | |||
| 2 | 2 | 5 | 0 | ||
| + | 2 | 5 | 0 | 0 | 0 |
| 2 | 7 | 3 | 5 | 0 |
The solution is: 27,350
How did we do?
Please leave us feedback.