Solution - Long multiplication

Because the ones digit of the multiplicator equals 0, skip to the next digit.

Proceed by multiplying the tens digit (3) of the multiplier (30) by each digit of the multiplicand (45,419), from right to left.

Because digit (3) is in tens place, we shift partial result by 1 place(s) by placing 1 zero(s).

Multiply the tens digit (3) of the multiplicator by the number in the ones place value:
3×9=27

Write 7 in the tens place.

Because the result is greater than 9, carry the 2 to the hundreds place.

Multiply the tens digit (3) of the multiplicator by the number in the tens place value and add the carried number (2):
3×1+2=5

Write 5 in the hundreds place.

Multiply the tens digit (3) of the multiplicator by the number in the hundreds place value:
3×4=12

Write 2 in the thousands place.

Because the result is greater than 9, carry the 1 to the ten thousands place.

Multiply the tens digit (3) of the multiplicator by the number in the thousands place value and add the carried number (1):
3×5+1=16

Write 6 in the ten thousands place.

Because the result is greater than 9, carry the 1 to the hundred thousands place.

Multiply the tens digit (3) of the multiplicator by the number in the ten thousands place value and add the carried number (1):
3×4+1=13

Write 3 in the hundred thousands place.

Because the result is greater than 9, carry the 1 to the millions place.

1,362,570 is the first partial product.

1362570=1362570 long addition steps can be seen here

The solution is: 1,362,570