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Solution - Absolute value equations

Exact form: x=-12,110
x=-\frac{1}{2} , \frac{1}{10}
Decimal form: x=0.5,0.1
x=-0.5 , 0.1

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|4x1|=|6x|
without the absolute value bars:

|x|=|y||4x1|=|6x|
x=+y(4x1)=(6x)
x=y(4x1)=(6x)
+x=y(4x1)=(6x)
x=y(4x1)=(6x)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||4x1|=|6x|
x=+y , +x=y(4x1)=(6x)
x=y , x=y(4x1)=(6x)

2. Solve the two equations for x

10 additional steps

(4x-1)=6x

Subtract from both sides:

(4x-1)-6x=(6x)-6x

Group like terms:

(4x-6x)-1=(6x)-6x

Simplify the arithmetic:

-2x-1=(6x)-6x

Simplify the arithmetic:

2x1=0

Add to both sides:

(-2x-1)+1=0+1

Simplify the arithmetic:

2x=0+1

Simplify the arithmetic:

2x=1

Divide both sides by :

(-2x)-2=1-2

Cancel out the negatives:

2x2=1-2

Simplify the fraction:

x=1-2

Move the negative sign from the denominator to the numerator:

x=-12

7 additional steps

(4x-1)=-6x

Add to both sides:

(4x-1)+1=(-6x)+1

Simplify the arithmetic:

4x=(-6x)+1

Add to both sides:

(4x)+6x=((-6x)+1)+6x

Simplify the arithmetic:

10x=((-6x)+1)+6x

Group like terms:

10x=(-6x+6x)+1

Simplify the arithmetic:

10x=1

Divide both sides by :

(10x)10=110

Simplify the fraction:

x=110

3. List the solutions

x=-12,110
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|4x1|
y=|6x|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.