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Nonlinear equations

Step by Step Solution

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                     10*k^6-(6*k-9)=0 

Step  1  :

Equation at the end of step  1  :

  (2•5k6) -  (6k - 9)  = 0 

Step  2  :

Polynomial Roots Calculator :

 2.1    Find roots (zeroes) of :       F(k) = 10k6-6k+9
Polynomial Roots Calculator is a set of methods aimed at finding values of  k  for which   F(k)=0  

Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers  k  which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number  P/Q   then  P  is a factor of the Trailing Constant and  Q  is a factor of the Leading Coefficient

In this case, the Leading Coefficient is  10  and the Trailing Constant is  9.

 
The factor(s) are:

of the Leading Coefficient :  1,2 ,5 ,10
 
of the Trailing Constant :  1 ,3 ,9

 
Let us test ....

  P  Q  P/Q  F(P/Q)   Divisor
     -1     1      -1.00      25.00   
     -1     2      -0.50      12.16   
     -1     5      -0.20      10.20   
     -1     10      -0.10      9.60   
     -3     1      -3.00      7317.00   


Note - For tidiness, printing of 19 checks which found no root was suppressed

Polynomial Roots Calculator found no rational roots

Equation at the end of step  2  :

  10k6 - 6k + 9  = 0 

Step  3  :

Equations of order 5 or higher :

 3.1     Solve   10k6-6k+9 = 0

In search of an interavl at which the above polynomial changes sign, from negative to positive or the other wayaround.

Method of search: Calculate polynomial values for all integer points between k=-20 and k=+20

No interval at which a change of sign occures has been found. Consequently, Bisection Approximation can not be used. As this is a polynomial of an even degree it may not even have any real (as opposed to imaginary) roots

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