Solution - Linear equations with one unknown
Other Ways to Solve
Linear equations with one unknownStep by Step Solution
Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
2*(y^3)-(12)=0
Step by step solution :
Step 1 :
Equation at the end of step 1 :
2y3 - 12 = 0
Step 2 :
Step 3 :
Pulling out like terms :
3.1 Pull out like factors :
2y3 - 12 = 2 • (y3 - 6)
Trying to factor as a Difference of Cubes:
3.2 Factoring: y3 - 6
Theory : A difference of two perfect cubes, a3 - b3 can be factored into
(a-b) • (a2 +ab +b2)
Proof : (a-b)•(a2+ab+b2) =
a3+a2b+ab2-ba2-b2a-b3 =
a3+(a2b-ba2)+(ab2-b2a)-b3 =
a3+0+0-b3 =
a3-b3
Check : 6 is not a cube !!
Ruling : Binomial can not be factored as the difference of two perfect cubes
Polynomial Roots Calculator :
3.3 Find roots (zeroes) of : F(y) = y3 - 6
Polynomial Roots Calculator is a set of methods aimed at finding values of y for which F(y)=0
Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers y which can be expressed as the quotient of two integers
The Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading Coefficient
In this case, the Leading Coefficient is 1 and the Trailing Constant is -6.
The factor(s) are:
of the Leading Coefficient : 1
of the Trailing Constant : 1 ,2 ,3 ,6
Let us test ....
P | Q | P/Q | F(P/Q) | Divisor | |||||
---|---|---|---|---|---|---|---|---|---|
-1 | 1 | -1.00 | -7.00 | ||||||
-2 | 1 | -2.00 | -14.00 | ||||||
-3 | 1 | -3.00 | -33.00 | ||||||
-6 | 1 | -6.00 | -222.00 | ||||||
1 | 1 | 1.00 | -5.00 | ||||||
2 | 1 | 2.00 | 2.00 | ||||||
3 | 1 | 3.00 | 21.00 | ||||||
6 | 1 | 6.00 | 210.00 |
Polynomial Roots Calculator found no rational roots
Equation at the end of step 3 :
2 • (y3 - 6) = 0
Step 4 :
Equations which are never true :
4.1 Solve : 2 = 0
This equation has no solution.
A a non-zero constant never equals zero.
Solving a Single Variable Equation :
4.2 Solve : y3-6 = 0
Add 6 to both sides of the equation :
y3 = 6
When two things are equal, their cube roots are equal. Taking the cube root of the two sides of the equation we get:
y = ∛ 6
The equation has one real solution
This solution is y = ∛6 = 1.8171
One solution was found :
y = ∛6 = 1.8171How did we do?
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