Solution - Adding, subtracting and finding the least common multiple
Other Ways to Solve
Adding, subtracting and finding the least common multipleStep by Step Solution
Step 1 :
1
Simplify —
8
Equation at the end of step 1 :
3 1
(— • a) - (— • a5)
4 8
Step 2 :
Equation at the end of step 2 :
3 a5
(— • a) - ——
4 8
Step 3 :
3
Simplify —
4
Equation at the end of step 3 :
3 a5
(— • a) - ——
4 8
Step 4 :
Calculating the Least Common Multiple :
4.1 Find the Least Common Multiple
The left denominator is : 4
The right denominator is : 8
| Prime Factor | Left Denominator | Right Denominator | L.C.M = Max {Left,Right} |
|---|---|---|---|
| 2 | 2 | 3 | 3 |
| Product of all Prime Factors | 4 | 8 | 8 |
Least Common Multiple:
8
Calculating Multipliers :
4.2 Calculate multipliers for the two fractions
Denote the Least Common Multiple by L.C.M
Denote the Left Multiplier by Left_M
Denote the Right Multiplier by Right_M
Denote the Left Deniminator by L_Deno
Denote the Right Multiplier by R_Deno
Left_M = L.C.M / L_Deno = 2
Right_M = L.C.M / R_Deno = 1
Making Equivalent Fractions :
4.3 Rewrite the two fractions into equivalent fractions
Two fractions are called equivalent if they have the same numeric value.
For example : 1/2 and 2/4 are equivalent, y/(y+1)2 and (y2+y)/(y+1)3 are equivalent as well.
To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.
L. Mult. • L. Num. 3a • 2 —————————————————— = —————— L.C.M 8 R. Mult. • R. Num. a5 —————————————————— = —— L.C.M 8
Adding fractions that have a common denominator :
4.4 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
3a • 2 - (a5) 6a - a5
————————————— = ———————
8 8
Step 5 :
Pulling out like terms :
5.1 Pull out like factors :
6a - a5 = -a • (a4 - 6)
Trying to factor as a Difference of Squares :
5.2 Factoring: a4 - 6
Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)
Proof : (A+B) • (A-B) =
A2 - AB + BA - B2 =
A2 - AB + AB - B2 =
A2 - B2
Note : AB = BA is the commutative property of multiplication.
Note : - AB + AB equals zero and is therefore eliminated from the expression.
Check : 6 is not a square !!
Ruling : Binomial can not be factored as the difference of two perfect squares.
Polynomial Roots Calculator :
5.3 Find roots (zeroes) of : F(a) = a4 - 6
Polynomial Roots Calculator is a set of methods aimed at finding values of a for which F(a)=0
Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers a which can be expressed as the quotient of two integers
The Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading Coefficient
In this case, the Leading Coefficient is 1 and the Trailing Constant is -6.
The factor(s) are:
of the Leading Coefficient : 1
of the Trailing Constant : 1 ,2 ,3 ,6
Let us test ....
| P | Q | P/Q | F(P/Q) | Divisor | |||||
|---|---|---|---|---|---|---|---|---|---|
| -1 | 1 | -1.00 | -5.00 | ||||||
| -2 | 1 | -2.00 | 10.00 | ||||||
| -3 | 1 | -3.00 | 75.00 | ||||||
| -6 | 1 | -6.00 | 1290.00 | ||||||
| 1 | 1 | 1.00 | -5.00 | ||||||
| 2 | 1 | 2.00 | 10.00 | ||||||
| 3 | 1 | 3.00 | 75.00 | ||||||
| 6 | 1 | 6.00 | 1290.00 |
Polynomial Roots Calculator found no rational roots
Final result :
+a • (a4 + 6)
—————————————
8
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