Solution - Factoring binomials using the difference of squares
Other Ways to Solve
Factoring binomials using the difference of squaresStep by Step Solution
Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
3*(4*x^2)-(6*(2*1))=0
Step by step solution :
Step 1 :
Equation at the end of step 1 :
(3 • 22x2) - 12 = 0
Step 2 :
Equation at the end of step 2 :
(3•22x2) - 12 = 0
Step 3 :
Step 4 :
Pulling out like terms :
4.1 Pull out like factors :
12x2 - 12 = 12 • (x2 - 1)
Trying to factor as a Difference of Squares :
4.2 Factoring: x2 - 1
Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)
Proof : (A+B) • (A-B) =
A2 - AB + BA - B2 =
A2 - AB + AB - B2 =
A2 - B2
Note : AB = BA is the commutative property of multiplication.
Note : - AB + AB equals zero and is therefore eliminated from the expression.
Check : 1 is the square of 1
Check : x2 is the square of x1
Factorization is : (x + 1) • (x - 1)
Equation at the end of step 4 :
12 • (x + 1) • (x - 1) = 0
Step 5 :
Theory - Roots of a product :
5.1 A product of several terms equals zero.
When a product of two or more terms equals zero, then at least one of the terms must be zero.
We shall now solve each term = 0 separately
In other words, we are going to solve as many equations as there are terms in the product
Any solution of term = 0 solves product = 0 as well.
Equations which are never true :
5.2 Solve : 12 = 0
This equation has no solution.
A a non-zero constant never equals zero.
Solving a Single Variable Equation :
5.3 Solve : x+1 = 0
Subtract 1 from both sides of the equation :
x = -1
Solving a Single Variable Equation :
5.4 Solve : x-1 = 0
Add 1 to both sides of the equation :
x = 1
Two solutions were found :
- x = 1
- x = -1
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