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Solution - Factoring binomials using the difference of squares

x=1
x=1
x=1
x=-1

Step by Step Solution

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                     3*(4*x^2)-(6*(2*1))=0 

Step by step solution :

Step  1  :

Equation at the end of step  1  :

  (3 • 22x2) -  12  = 0 

Step  2  :

Equation at the end of step  2  :

  (3•22x2) -  12  = 0 

Step  3  :

Step  4  :

Pulling out like terms :

 4.1     Pull out like factors :

   12x2 - 12  =   12 • (x2 - 1) 

Trying to factor as a Difference of Squares :

 4.2      Factoring:  x2 - 1 

Theory : A difference of two perfect squares,  A2 - B2  can be factored into  (A+B) • (A-B)

Proof :  (A+B) • (A-B) =
         A2 - AB + BA - B2 =
         A2 - AB + AB - B2 =
         A2 - B2

Note :  AB = BA is the commutative property of multiplication.

Note :  - AB + AB equals zero and is therefore eliminated from the expression.

Check : 1 is the square of 1
Check :  x2  is the square of  x1 

Factorization is :       (x + 1)  •  (x - 1) 

Equation at the end of step  4  :

  12 • (x + 1) • (x - 1)  = 0 

Step  5  :

Theory - Roots of a product :

 5.1    A product of several terms equals zero. 

 
When a product of two or more terms equals zero, then at least one of the terms must be zero. 

 
We shall now solve each term = 0 separately 

 
In other words, we are going to solve as many equations as there are terms in the product 

 
Any solution of term = 0 solves product = 0 as well.

Equations which are never true :

 5.2      Solve :    12   =  0

This equation has no solution.
A a non-zero constant never equals zero.

Solving a Single Variable Equation :

 5.3      Solve  :    x+1 = 0 

 
Subtract  1  from both sides of the equation : 
 
                     x = -1

Solving a Single Variable Equation :

 5.4      Solve  :    x-1 = 0 

 
Add  1  to both sides of the equation : 
 
                     x = 1

Two solutions were found :

  1.  x = 1
  2.  x = -1

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