Solution - Linear equations with one unknown
Other Ways to Solve
Linear equations with one unknownStep by Step Solution
Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
48*x^3-(3)=0
Step by step solution :
Step 1 :
Equation at the end of step 1 :
(24•3x3) - 3 = 0
Step 2 :
Step 3 :
Pulling out like terms :
3.1 Pull out like factors :
48x3 - 3 = 3 • (16x3 - 1)
Trying to factor as a Difference of Cubes:
3.2 Factoring: 16x3 - 1
Theory : A difference of two perfect cubes, a3 - b3 can be factored into
(a-b) • (a2 +ab +b2)
Proof : (a-b)•(a2+ab+b2) =
a3+a2b+ab2-ba2-b2a-b3 =
a3+(a2b-ba2)+(ab2-b2a)-b3 =
a3+0+0-b3 =
a3-b3
Check : 16 is not a cube !!
Ruling : Binomial can not be factored as the difference of two perfect cubes
Polynomial Roots Calculator :
3.3 Find roots (zeroes) of : F(x) = 16x3 - 1
Polynomial Roots Calculator is a set of methods aimed at finding values of x for which F(x)=0
Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers x which can be expressed as the quotient of two integers
The Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading Coefficient
In this case, the Leading Coefficient is 16 and the Trailing Constant is -1.
The factor(s) are:
of the Leading Coefficient : 1,2 ,4 ,8 ,16
of the Trailing Constant : 1
Let us test ....
P | Q | P/Q | F(P/Q) | Divisor | |||||
---|---|---|---|---|---|---|---|---|---|
-1 | 1 | -1.00 | -17.00 | ||||||
-1 | 2 | -0.50 | -3.00 | ||||||
-1 | 4 | -0.25 | -1.25 | ||||||
-1 | 8 | -0.12 | -1.03 | ||||||
-1 | 16 | -0.06 | -1.00 | ||||||
1 | 1 | 1.00 | 15.00 | ||||||
1 | 2 | 0.50 | 1.00 | ||||||
1 | 4 | 0.25 | -0.75 | ||||||
1 | 8 | 0.12 | -0.97 | ||||||
1 | 16 | 0.06 | -1.00 |
Polynomial Roots Calculator found no rational roots
Equation at the end of step 3 :
3 • (16x3 - 1) = 0
Step 4 :
Equations which are never true :
4.1 Solve : 3 = 0
This equation has no solution.
A a non-zero constant never equals zero.
Solving a Single Variable Equation :
4.2 Solve : 16x3-1 = 0
Add 1 to both sides of the equation :
16x3 = 1
Divide both sides of the equation by 16:
x3 = 1/16 = 0.062
When two things are equal, their cube roots are equal. Taking the cube root of the two sides of the equation we get:
x = ∛ 1/16
The equation has one real solution
This solution is x = ∛ 0.062 = 0.39685
One solution was found :
x = ∛ 0.062 = 0.39685How did we do?
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