Solution - Linear equations with one unknown
Other Ways to Solve
Linear equations with one unknownStep by Step Solution
Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
5*x^45-(30)=0
Step by step solution :
Step 1 :
Equation at the end of step 1 :
5x45 - 30 = 0
Step 2 :
Step 3 :
Pulling out like terms :
3.1 Pull out like factors :
5x45 - 30 = 5 • (x45 - 6)
Trying to factor as a Difference of Cubes:
3.2 Factoring: x45 - 6
Theory : A difference of two perfect cubes, a3 - b3 can be factored into
(a-b) • (a2 +ab +b2)
Proof : (a-b)•(a2+ab+b2) =
a3+a2b+ab2-ba2-b2a-b3 =
a3+(a2b-ba2)+(ab2-b2a)-b3 =
a3+0+0-b3 =
a3-b3
Check : 6 is not a cube !!
Ruling : Binomial can not be factored as the difference of two perfect cubes
Equation at the end of step 3 :
5 • (x45 - 6) = 0
Step 4 :
Equations which are never true :
4.1 Solve : 5 = 0
This equation has no solution.
A a non-zero constant never equals zero.
Solving a Single Variable Equation :
4.2 Solve : x45-6 = 0
Add 6 to both sides of the equation :
x45 = 6
x = 45th root of (6)
The equation has one real solution
This solution is x = 45th root of 6 = 1.0406
One solution was found :
x = 45th root of 6 = 1.0406How did we do?
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