Solution - Linear equations with one unknown
Other Ways to Solve
Linear equations with one unknownStep by Step Solution
Reformatting the input :
Changes made to your input should not affect the solution:
(1): "n1" was replaced by "n^1".
Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
8*n-3*n^15-(4*n^25)=0
Step by step solution :
Step 1 :
Equation at the end of step 1 :
(8n - (3 • (n15))) - 22n25 = 0Step 2 :
Equation at the end of step 2 :
(8n - 3n15) - 22n25 = 0
Step 3 :
Step 4 :
Pulling out like terms :
4.1 Pull out like factors :
-4n25 - 3n15 + 8n = -n • (4n24 + 3n14 - 8)
Equation at the end of step 4 :
-n • (4n24 + 3n14 - 8) = 0
Step 5 :
Theory - Roots of a product :
5.1 A product of several terms equals zero.
When a product of two or more terms equals zero, then at least one of the terms must be zero.
We shall now solve each term = 0 separately
In other words, we are going to solve as many equations as there are terms in the product
Any solution of term = 0 solves product = 0 as well.
Solving a Single Variable Equation :
5.2 Solve : -n = 0
Multiply both sides of the equation by (-1) : n = 0
Equations of order 5 or higher :
5.3 Solve 4n24+3n14-8 = 0
Handling of functions of an even degree greater than 6 is not implemented yet
One solution was found :
n = 0How did we do?
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