Solution - Reducing fractions to their lowest terms
Other Ways to Solve
Reducing fractions to their lowest termsStep by Step Solution
Step 1 :
x27
Simplify ———
h
Equation at the end of step 1 :
x27
(g•(((x23)•(x4))•h))-(g•———)
h
Step 2 :
Rewriting the whole as an Equivalent Fraction :
2.1 Subtracting a fraction from a whole
Rewrite the whole as a fraction using h as the denominator :
gx27h gx27h • h
gx27h = ————— = —————————
1 h
Equivalent fraction : The fraction thus generated looks different but has the same value as the whole
Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator
Adding fractions that have a common denominator :
2.2 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
gx27h • h - (gx27) gx27h2 - gx27
—————————————————— = —————————————
h h
Step 3 :
Pulling out like terms :
3.1 Pull out like factors :
gx27h2 - gx27 = gx27 • (h2 - 1)
Trying to factor as a Difference of Squares :
3.2 Factoring: h2 - 1
Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)
Proof : (A+B) • (A-B) =
A2 - AB + BA - B2 =
A2 - AB + AB - B2 =
A2 - B2
Note : AB = BA is the commutative property of multiplication.
Note : - AB + AB equals zero and is therefore eliminated from the expression.
Check : 1 is the square of 1
Check : h2 is the square of h1
Factorization is : (h + 1) • (h - 1)
Final result :
gx27 • (h + 1) • (h - 1)
————————————————————————
h
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