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Factoring binomials using the difference of squaresStep by Step Solution
Reformatting the input :
Changes made to your input should not affect the solution:
(1): "x1" was replaced by "x^1". 1 more similar replacement(s).
Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
k-(y^1*y^2/x^1*x^2)=0
Step 1 :
y2
Simplify ——
x
Equation at the end of step 1 :
y2 k - (((y1) • ——) • x2) = 0 xStep 2 :
Trying to factor as a Difference of Cubes:
2.1 Factoring: k-y3x
Theory : A difference of two perfect cubes, a3 - b3 can be factored into
(a-b) • (a2 +ab +b2)
Proof : (a-b)•(a2+ab+b2) =
a3+a2b+ab2-ba2-b2a-b3 =
a3+(a2b-ba2)+(ab2-b2a)-b3 =
a3+0+0-b3 =
a3-b3
Check : k 1 is not a cube !!
Ruling : Binomial can not be factored as the difference of two perfect cubes
Equation at the end of step 2 :
k - y3x = 0
Step 3 :
Solving a Single Variable Equation :
3.1 Solve k-y3x = 0
In this type of equations, having more than one variable (unknown), you have to specify for which variable you want the equation solved.
We shall not handle this type of equations at this time.
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