Solution - Factoring binomials using the difference of squares

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                     v*v-6-(3)=0 

Step by step solution :

Trying to factor as a Difference of Squares :

 0.1      Factoring:  v² - 9 

Theory : A difference of two perfect squares,  A² - B²  can be factored into  (A+B) • (A-B)

Proof :  (A+B) • (A-B) =
         A² - AB + BA - B² =
         A² - AB + AB - B² =
         A² - B²

Note :  AB = BA is the commutative property of multiplication.

Note :  - AB + AB equals zero and is therefore eliminated from the expression.

Check : 9 is the square of 3
Check :  v²  is the square of  v¹ 

Factorization is :       (v + 3)  •  (v - 3) 

Step  1  :

Theory - Roots of a product :

 1.1    A product of several terms equals zero. 

 When a product of two or more terms equals zero, then at least one of the terms must be zero. 

 We shall now solve each term = 0 separately 

 In other words, we are going to solve as many equations as there are terms in the product 

 Any solution of term = 0 solves product = 0 as well.

Solving a Single Variable Equation :

 1.2      Solve  :    v+3 = 0 

 Subtract  3  from both sides of the equation : 
                      v = -3

Solving a Single Variable Equation :

 1.3      Solve  :    v-3 = 0 

 Add  3  to both sides of the equation : 
                      v = 3

Two solutions were found :

1.  v = 3
2.  v = -3