Solution - Finding the roots of polynomials
Other Ways to Solve
Finding the roots of polynomialsStep by Step Solution
Step 1 :
Step 2 :
Pulling out like terms :
2.1 Pull out like factors :
x21 - x = x • (x20 - 1)
Trying to factor as a Difference of Squares :
2.2 Factoring: x20 - 1
Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)
Proof : (A+B) • (A-B) =
A2 - AB + BA - B2 =
A2 - AB + AB - B2 =
A2 - B2
Note : AB = BA is the commutative property of multiplication.
Note : - AB + AB equals zero and is therefore eliminated from the expression.
Check : 1 is the square of 1
Check : x20 is the square of x10
Factorization is : (x10 + 1) • (x10 - 1)
Trying to factor as a Difference of Squares :
2.3 Factoring: x10 - 1
Check : 1 is the square of 1
Check : x10 is the square of x5
Factorization is : (x5 + 1) • (x5 - 1)
Polynomial Roots Calculator :
2.4 Find roots (zeroes) of : F(x) = x5 + 1
Polynomial Roots Calculator is a set of methods aimed at finding values of x for which F(x)=0
Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers x which can be expressed as the quotient of two integers
The Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading Coefficient
In this case, the Leading Coefficient is 1 and the Trailing Constant is 1.
The factor(s) are:
of the Leading Coefficient : 1
of the Trailing Constant : 1
Let us test ....
P | Q | P/Q | F(P/Q) | Divisor | |||||
---|---|---|---|---|---|---|---|---|---|
-1 | 1 | -1.00 | 0.00 | x + 1 | |||||
1 | 1 | 1.00 | 2.00 |
The Factor Theorem states that if P/Q is root of a polynomial then this polynomial can be divided by q*x-p Note that q and p originate from P/Q reduced to its lowest terms
In our case this means that
x5 + 1
can be divided with x + 1
Polynomial Long Division :
2.5 Polynomial Long Division
Dividing : x5 + 1
("Dividend")
By : x + 1 ("Divisor")
dividend | x5 | + | 1 | ||||||||||
- divisor | * x4 | x5 | + | x4 | |||||||||
remainder | - | x4 | + | 1 | |||||||||
- divisor | * -x3 | - | x4 | - | x3 | ||||||||
remainder | x3 | + | 1 | ||||||||||
- divisor | * x2 | x3 | + | x2 | |||||||||
remainder | - | x2 | + | 1 | |||||||||
- divisor | * -x1 | - | x2 | - | x | ||||||||
remainder | x | + | 1 | ||||||||||
- divisor | * x0 | x | + | 1 | |||||||||
remainder | 0 |
Quotient : x4-x3+x2-x+1 Remainder: 0
Polynomial Roots Calculator :
2.6 Find roots (zeroes) of : F(x) = x4-x3+x2-x+1
See theory in step 2.4
In this case, the Leading Coefficient is 1 and the Trailing Constant is 1.
The factor(s) are:
of the Leading Coefficient : 1
of the Trailing Constant : 1
Let us test ....
P | Q | P/Q | F(P/Q) | Divisor | |||||
---|---|---|---|---|---|---|---|---|---|
-1 | 1 | -1.00 | 5.00 | ||||||
1 | 1 | 1.00 | 1.00 |
Polynomial Roots Calculator found no rational roots
Polynomial Roots Calculator :
2.7 Find roots (zeroes) of : F(x) = x5-1
See theory in step 2.4
In this case, the Leading Coefficient is 1 and the Trailing Constant is -1.
The factor(s) are:
of the Leading Coefficient : 1
of the Trailing Constant : 1
Let us test ....
P | Q | P/Q | F(P/Q) | Divisor | |||||
---|---|---|---|---|---|---|---|---|---|
-1 | 1 | -1.00 | -2.00 | ||||||
1 | 1 | 1.00 | 0.00 | x-1 |
The Factor Theorem states that if P/Q is root of a polynomial then this polynomial can be divided by q*x-p Note that q and p originate from P/Q reduced to its lowest terms
In our case this means that
x5-1
can be divided with x-1
Polynomial Long Division :
2.8 Polynomial Long Division
Dividing : x5-1
("Dividend")
By : x-1 ("Divisor")
dividend | x5 | - | 1 | ||||||||||
- divisor | * x4 | x5 | - | x4 | |||||||||
remainder | x4 | - | 1 | ||||||||||
- divisor | * x3 | x4 | - | x3 | |||||||||
remainder | x3 | - | 1 | ||||||||||
- divisor | * x2 | x3 | - | x2 | |||||||||
remainder | x2 | - | 1 | ||||||||||
- divisor | * x1 | x2 | - | x | |||||||||
remainder | x | - | 1 | ||||||||||
- divisor | * x0 | x | - | 1 | |||||||||
remainder | 0 |
Quotient : x4+x3+x2+x+1 Remainder: 0
Polynomial Roots Calculator :
2.9 Find roots (zeroes) of : F(x) = x4+x3+x2+x+1
See theory in step 2.4
In this case, the Leading Coefficient is 1 and the Trailing Constant is 1.
The factor(s) are:
of the Leading Coefficient : 1
of the Trailing Constant : 1
Let us test ....
P | Q | P/Q | F(P/Q) | Divisor | |||||
---|---|---|---|---|---|---|---|---|---|
-1 | 1 | -1.00 | 1.00 | ||||||
1 | 1 | 1.00 | 5.00 |
Polynomial Roots Calculator found no rational roots
Final result :
x•(x10+1)•(x4-x3+x2-x+1)•(x+1)•(x4+x3+x2+x+1)•(x-1)
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