Solution - Long multiplication
Other Ways to Solve:
Step-by-step explanation
1. Rewrite the numbers from top to bottom aligned to the right
Place value | hundred thousands | ten thousands | thousands | hundreds | tens | ones | . | tenths | hundredths |
0 | . | 0 | 3 | ||||||
× | 1 | 5 | 0 | 0 | 0 | 0 | |||
Ignore the decimal points and multiply as if these are whole numbers (as if each most right digit is the ones digit):
In this case we removed 2 decimal place(s). So once calculated, the result will be reduced by the factor of 100.
Place value | hundred thousands | ten thousands | thousands | hundreds | tens | ones |
3 | ||||||
× | 1 | 5 | 0 | 0 | 0 | 0 |
2. Multiply the numbers using long multiplication method
Because the thousands digit of the multiplicator equals 0, skip to the next digit.
Proceed by multiplying the ten thousands digit (5) of the multiplier (150,000) by each digit of the multiplicand (3), from right to left.
Because digit (5) is in ten thousands place, we shift partial result by 4 place(s) by placing 4 zero(s).
Place value | hundred thousands | ten thousands | thousands | hundreds | tens | ones |
3 | ||||||
× | 1 | 5 | 0 | 0 | 0 | 0 |
0 | 0 | 0 | 0 | |||
Multiply the ten thousands digit (5) of the multiplicator by the number in the ones place value:
5×3=15
Write 5 in the ten thousands place.
Because the result is greater than 9, carry the 1 to the hundred thousands place.
Place value | hundred thousands | ten thousands | thousands | hundreds | tens | ones |
1 | ||||||
3 | ||||||
× | 1 | 5 | 0 | 0 | 0 | 0 |
1 | 5 | 0 | 0 | 0 | 0 | |
150,000 is the first partial product.
Proceed by multiplying the hundred thousands digit (1) of the multiplier (150,000) by each digit of the multiplicand (3), from right to left.
Because digit (1) is in hundred thousands place, we shift partial result by 5 place(s) by placing 5 zero(s).
Place value | hundred thousands | ten thousands | thousands | hundreds | tens | ones |
3 | ||||||
× | 1 | 5 | 0 | 0 | 0 | 0 |
1 | 5 | 0 | 0 | 0 | 0 | |
0 | 0 | 0 | 0 | 0 |
Multiply the hundred thousands digit (1) of the multiplicator by the number in the ones place value:
1×3=3
Write 3 in the hundred thousands place.
Place value | hundred thousands | ten thousands | thousands | hundreds | tens | ones |
3 | ||||||
× | 1 | 5 | 0 | 0 | 0 | 0 |
1 | 5 | 0 | 0 | 0 | 0 | |
3 | 0 | 0 | 0 | 0 | 0 |
300,000 is the second partial product.
3. Add the partial products
150000+300000=450000 long addition steps can be seen here
Place value | hundred thousands | ten thousands | thousands | hundreds | tens | ones |
3 | ||||||
× | 1 | 5 | 0 | 0 | 0 | 0 |
1 | 5 | 0 | 0 | 0 | 0 | |
+ | 3 | 0 | 0 | 0 | 0 | 0 |
4 | 5 | 0 | 0 | 0 | 0 |
Because we have 2 digit(s) to the right of the decimal point in the numbers that are being multiplied, we move the decimal point 2 time(s) to the left (reducing the result by the factor of 100) to get the final result:
The solution is: 4,500
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