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Solution - Absolute value equations

Exact form: m=3,-113
m=3 , -\frac{11}{3}
Mixed number form: m=3,-323
m=3 , -3\frac{2}{3}
Decimal form: m=3,3.667
m=3 , -3.667

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|m+7|=2|m+2|
without the absolute value bars:

|x|=|y||m+7|=2|m+2|
x=+y(m+7)=2(m+2)
x=y(m+7)=2((m+2))
+x=y(m+7)=2(m+2)
x=y(m+7)=2(m+2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||m+7|=2|m+2|
x=+y , +x=y(m+7)=2(m+2)
x=y , x=y(m+7)=2((m+2))

2. Solve the two equations for m

12 additional steps

(m+7)=2·(m+2)

Expand the parentheses:

(m+7)=2m+2·2

Simplify the arithmetic:

(m+7)=2m+4

Subtract from both sides:

(m+7)-2m=(2m+4)-2m

Group like terms:

(m-2m)+7=(2m+4)-2m

Simplify the arithmetic:

-m+7=(2m+4)-2m

Group like terms:

-m+7=(2m-2m)+4

Simplify the arithmetic:

-m+7=4

Subtract from both sides:

(-m+7)-7=4-7

Simplify the arithmetic:

-m=4-7

Simplify the arithmetic:

-m=-3

Multiply both sides by :

-m·-1=-3·-1

Remove the one(s):

m=-3·-1

Simplify the arithmetic:

m=3

14 additional steps

(m+7)=2·(-(m+2))

Expand the parentheses:

(m+7)=2·(-m-2)

(m+7)=2·-m+2·-2

Group like terms:

(m+7)=(2·-1)m+2·-2

Multiply the coefficients:

(m+7)=-2m+2·-2

Simplify the arithmetic:

(m+7)=-2m-4

Add to both sides:

(m+7)+2m=(-2m-4)+2m

Group like terms:

(m+2m)+7=(-2m-4)+2m

Simplify the arithmetic:

3m+7=(-2m-4)+2m

Group like terms:

3m+7=(-2m+2m)-4

Simplify the arithmetic:

3m+7=-4

Subtract from both sides:

(3m+7)-7=-4-7

Simplify the arithmetic:

3m=-4-7

Simplify the arithmetic:

3m=-11

Divide both sides by :

(3m)3=-113

Simplify the fraction:

m=-113

3. List the solutions

m=3,-113
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|m+7|
y=2|m+2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.