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Solution - Absolute value equations

Exact form: x=4,2
x=4 , 2

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x12|=|3x4|
without the absolute value bars:

|x|=|y||5x12|=|3x4|
x=+y(5x12)=(3x4)
x=y(5x12)=(3x4)
+x=y(5x12)=(3x4)
x=y(5x12)=(3x4)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x12|=|3x4|
x=+y , +x=y(5x12)=(3x4)
x=y , x=y(5x12)=(3x4)

2. Solve the two equations for x

11 additional steps

(5x-12)=(3x-4)

Subtract from both sides:

(5x-12)-3x=(3x-4)-3x

Group like terms:

(5x-3x)-12=(3x-4)-3x

Simplify the arithmetic:

2x-12=(3x-4)-3x

Group like terms:

2x-12=(3x-3x)-4

Simplify the arithmetic:

2x12=4

Add to both sides:

(2x-12)+12=-4+12

Simplify the arithmetic:

2x=4+12

Simplify the arithmetic:

2x=8

Divide both sides by :

(2x)2=82

Simplify the fraction:

x=82

Find the greatest common factor of the numerator and denominator:

x=(4·2)(1·2)

Factor out and cancel the greatest common factor:

x=4

12 additional steps

(5x-12)=-(3x-4)

Expand the parentheses:

(5x-12)=-3x+4

Add to both sides:

(5x-12)+3x=(-3x+4)+3x

Group like terms:

(5x+3x)-12=(-3x+4)+3x

Simplify the arithmetic:

8x-12=(-3x+4)+3x

Group like terms:

8x-12=(-3x+3x)+4

Simplify the arithmetic:

8x12=4

Add to both sides:

(8x-12)+12=4+12

Simplify the arithmetic:

8x=4+12

Simplify the arithmetic:

8x=16

Divide both sides by :

(8x)8=168

Simplify the fraction:

x=168

Find the greatest common factor of the numerator and denominator:

x=(2·8)(1·8)

Factor out and cancel the greatest common factor:

x=2

3. List the solutions

x=4,2
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5x12|
y=|3x4|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.