Solution - Quadratic equations
Other Ways to Solve:
Step by Step Solution
Step by step solution :
Step 1 :
Equation at the end of step 1 :
(23x2 - 75x) + 50 = 0
Step 2 :
Trying to factor by splitting the middle term
2.1 Factoring 23x2-75x+50
The first term is, 23x2 its coefficient is 23 .
The middle term is, -75x its coefficient is -75 .
The last term, "the constant", is +50
Step-1 : Multiply the coefficient of the first term by the constant 23 • 50 = 1150
Step-2 : Find two factors of 1150 whose sum equals the coefficient of the middle term, which is -75 .
-1150 | + | -1 | = | -1151 | ||
-575 | + | -2 | = | -577 | ||
-230 | + | -5 | = | -235 | ||
-115 | + | -10 | = | -125 | ||
-50 | + | -23 | = | -73 | ||
-46 | + | -25 | = | -71 |
For tidiness, printing of 18 lines which failed to find two such factors, was suppressed
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Equation at the end of step 2 :
23x2 - 75x + 50 = 0
Step 3 :
Parabola, Finding the Vertex :
3.1 Find the Vertex of y = 23x2-75x+50
Parabolas have a highest or a lowest point called the Vertex . Our parabola opens up and accordingly has a lowest point (AKA absolute minimum) . We know this even before plotting "y" because the coefficient of the first term, 23 , is positive (greater than zero).
Each parabola has a vertical line of symmetry that passes through its vertex. Because of this symmetry, the line of symmetry would, for example, pass through the midpoint of the two x -intercepts (roots or solutions) of the parabola. That is, if the parabola has indeed two real solutions.
Parabolas can model many real life situations, such as the height above ground, of an object thrown upward, after some period of time. The vertex of the parabola can provide us with information, such as the maximum height that object, thrown upwards, can reach. For this reason we want to be able to find the coordinates of the vertex.
For any parabola,Ax2+Bx+C,the x -coordinate of the vertex is given by -B/(2A) . In our case the x coordinate is 1.6304
Plugging into the parabola formula 1.6304 for x we can calculate the y -coordinate :
y = 23.0 * 1.63 * 1.63 - 75.0 * 1.63 + 50.0
or y = -11.141
Parabola, Graphing Vertex and X-Intercepts :
Root plot for : y = 23x2-75x+50
Axis of Symmetry (dashed) {x}={ 1.63}
Vertex at {x,y} = { 1.63,-11.14}
x -Intercepts (Roots) :
Root 1 at {x,y} = { 0.93, 0.00}
Root 2 at {x,y} = { 2.33, 0.00}
Solve Quadratic Equation by Completing The Square
3.2 Solving 23x2-75x+50 = 0 by Completing The Square .
Divide both sides of the equation by 23 to have 1 as the coefficient of the first term :
x2-(75/23)x+(50/23) = 0
Subtract 50/23 from both side of the equation :
x2-(75/23)x = -50/23
Now the clever bit: Take the coefficient of x , which is 75/23 , divide by two, giving 75/46 , and finally square it giving 5625/2116
Add 5625/2116 to both sides of the equation :
On the right hand side we have :
-50/23 + 5625/2116 The common denominator of the two fractions is 2116 Adding (-4600/2116)+(5625/2116) gives 1025/2116
So adding to both sides we finally get :
x2-(75/23)x+(5625/2116) = 1025/2116
Adding 5625/2116 has completed the left hand side into a perfect square :
x2-(75/23)x+(5625/2116) =
(x-(75/46)) • (x-(75/46)) =
(x-(75/46))2
Things which are equal to the same thing are also equal to one another. Since
x2-(75/23)x+(5625/2116) = 1025/2116 and
x2-(75/23)x+(5625/2116) = (x-(75/46))2
then, according to the law of transitivity,
(x-(75/46))2 = 1025/2116
We'll refer to this Equation as Eq. #3.2.1
The Square Root Principle says that When two things are equal, their square roots are equal.
Note that the square root of
(x-(75/46))2 is
(x-(75/46))2/2 =
(x-(75/46))1 =
x-(75/46)
Now, applying the Square Root Principle to Eq. #3.2.1 we get:
x-(75/46) = √ 1025/2116
Add 75/46 to both sides to obtain:
x = 75/46 + √ 1025/2116
Since a square root has two values, one positive and the other negative
x2 - (75/23)x + (50/23) = 0
has two solutions:
x = 75/46 + √ 1025/2116
or
x = 75/46 - √ 1025/2116
Note that √ 1025/2116 can be written as
√ 1025 / √ 2116 which is √ 1025 / 46
Solve Quadratic Equation using the Quadratic Formula
3.3 Solving 23x2-75x+50 = 0 by the Quadratic Formula .
According to the Quadratic Formula, x , the solution for Ax2+Bx+C = 0 , where A, B and C are numbers, often called coefficients, is given by :
- B ± √ B2-4AC
x = ————————
2A
In our case, A = 23
B = -75
C = 50
Accordingly, B2 - 4AC =
5625 - 4600 =
1025
Applying the quadratic formula :
75 ± √ 1025
x = ——————
46
Can √ 1025 be simplified ?
Yes! The prime factorization of 1025 is
5•5•41
To be able to remove something from under the radical, there have to be 2 instances of it (because we are taking a square i.e. second root).
√ 1025 = √ 5•5•41 =
± 5 • √ 41
√ 41 , rounded to 4 decimal digits, is 6.4031
So now we are looking at:
x = ( 75 ± 5 • 6.403 ) / 46
Two real solutions:
x =(75+√1025)/46=(75+5√ 41 )/46= 2.326
or:
x =(75-√1025)/46=(75-5√ 41 )/46= 0.934
Two solutions were found :
- x =(75-√1025)/46=(75-5√ 41 )/46= 0.934
- x =(75+√1025)/46=(75+5√ 41 )/46= 2.326
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