Solution - Simplification or other simple results
Other Ways to Solve:
Step by Step Solution
Step 1 :
Equation at the end of step 1 :
(2t2 + 7t) + 6
Step 2 :
Trying to factor by splitting the middle term
2.1 Factoring 2t2+7t+6
The first term is, 2t2 its coefficient is 2 .
The middle term is, +7t its coefficient is 7 .
The last term, "the constant", is +6
Step-1 : Multiply the coefficient of the first term by the constant 2 • 6 = 12
Step-2 : Find two factors of 12 whose sum equals the coefficient of the middle term, which is 7 .
| -12 | + | -1 | = | -13 | ||
| -6 | + | -2 | = | -8 | ||
| -4 | + | -3 | = | -7 | ||
| -3 | + | -4 | = | -7 | ||
| -2 | + | -6 | = | -8 | ||
| -1 | + | -12 | = | -13 | ||
| 1 | + | 12 | = | 13 | ||
| 2 | + | 6 | = | 8 | ||
| 3 | + | 4 | = | 7 | That's it |
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, 3 and 4
2t2 + 3t + 4t + 6
Step-4 : Add up the first 2 terms, pulling out like factors :
t • (2t+3)
Add up the last 2 terms, pulling out common factors :
2 • (2t+3)
Step-5 : Add up the four terms of step 4 :
(t+2) • (2t+3)
Which is the desired factorization
Final result :
(2t + 3) • (t + 2)
How did we do?
Please leave us feedback.