Solution - Adding, subtracting and finding the least common multiple

Step by step solution :

Step  1  :

            4
 Simplify   —
            3

Equation at the end of step  1  :

         1     4
  (3x -  —) +  —  = 0 
         3     3

Step  2  :

            1
 Simplify   —
            3

Equation at the end of step  2  :

         1     4
  (3x -  —) +  —  = 0 
         3     3

Step  3  :

Rewriting the whole as an Equivalent Fraction :

 3.1   Subtracting a fraction from a whole

Rewrite the whole as a fraction using  3  as the denominator :

           3x     3x • 3
     3x =  ——  =  ——————
           1        3   

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

 3.2       Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

 3x • 3 - (1)     9x - 1
 ————————————  =  ——————
      3             3   

Equation at the end of step  3  :

  (9x - 1)    4
  ———————— +  —  = 0 
     3        3

Step  4  :

Adding fractions which have a common denominator :

 4.1       Adding fractions which have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

 (9x-1) + 4     9x + 3
 ——————————  =  ——————
     3            3   

Step  5  :

Pulling out like terms :

 5.1     Pull out like factors :

   9x + 3  =   3 • (3x + 1) 

Equation at the end of step  5  :

  3x + 1  = 0 

Step  6  :

Solving a Single Variable Equation :

 6.1      Solve  :    3x+1 = 0 

 Subtract  1  from both sides of the equation : 
                      3x = -1
Divide both sides of the equation by 3:
                     x = -1/3 = -0.333

One solution was found :