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Solution - Absolute value equations

Exact form: x=5,53
x=5 , \frac{5}{3}
Mixed number form: x=5,123
x=5 , 1\frac{2}{3}
Decimal form: x=5,1.667
x=5 , 1.667

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|4x10|=|2x|
without the absolute value bars:

|x|=|y||4x10|=|2x|
x=+y(4x10)=(2x)
x=y(4x10)=(2x)
+x=y(4x10)=(2x)
x=y(4x10)=(2x)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||4x10|=|2x|
x=+y , +x=y(4x10)=(2x)
x=y , x=y(4x10)=(2x)

2. Solve the two equations for x

10 additional steps

(4x-10)=2x

Subtract from both sides:

(4x-10)-2x=(2x)-2x

Group like terms:

(4x-2x)-10=(2x)-2x

Simplify the arithmetic:

2x-10=(2x)-2x

Simplify the arithmetic:

2x10=0

Add to both sides:

(2x-10)+10=0+10

Simplify the arithmetic:

2x=0+10

Simplify the arithmetic:

2x=10

Divide both sides by :

(2x)2=102

Simplify the fraction:

x=102

Find the greatest common factor of the numerator and denominator:

x=(5·2)(1·2)

Factor out and cancel the greatest common factor:

x=5

9 additional steps

(4x-10)=-2x

Add to both sides:

(4x-10)+10=(-2x)+10

Simplify the arithmetic:

4x=(-2x)+10

Add to both sides:

(4x)+2x=((-2x)+10)+2x

Simplify the arithmetic:

6x=((-2x)+10)+2x

Group like terms:

6x=(-2x+2x)+10

Simplify the arithmetic:

6x=10

Divide both sides by :

(6x)6=106

Simplify the fraction:

x=106

Find the greatest common factor of the numerator and denominator:

x=(5·2)(3·2)

Factor out and cancel the greatest common factor:

x=53

3. List the solutions

x=5,53
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|4x10|
y=|2x|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.