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Solution - Simplification or other simple results
-z^2*(4z^31+1)*(4z^31-1)
Other Ways to Solve:
Step by Step Solution
Step 1 :
Equation at the end of step 1 :
(z2) - 24z64Step 2 :
Step 3 :
Pulling out like terms :
3.1 Pull out like factors :
z2 - 16z64 = -z2 • (16z62 - 1)
Trying to factor as a Difference of Squares :
3.2 Factoring: 16z62 - 1
Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)
Proof : (A+B) • (A-B) =
A2 - AB + BA - B2 =
A2 - AB + AB - B2 =
A2 - B2
Note : AB = BA is the commutative property of multiplication.
Note : - AB + AB equals zero and is therefore eliminated from the expression.
Check : 16 is the square of 4
Check : 1 is the square of 1
Check : z62 is the square of z31
Factorization is : (4z31 + 1) • (4z31 - 1)
Final result :
-z2 • (4z31 + 1) • (4z31 - 1)
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