Solution - Reducing fractions to their lowest terms
Other Ways to Solve:
Step by Step Solution
Reformatting the input :
Changes made to your input should not affect the solution:
 (1): "0.2" was replaced by "(2/10)".
Step 1 :
            1
 Simplify   —
            5
Equation at the end of step 1 :
    1                   
  ((— • x2) +  40x) -  2500
    5                   
Step 2 :
Equation at the end of step 2 :
   x2            
  (—— +  40x) -  2500
   5             
Step 3 :
Rewriting the whole as an Equivalent Fraction :
 3.1   Adding a whole to a fraction 
Rewrite the whole as a fraction using  5  as the denominator :
           40x     40x • 5
    40x =  ———  =  ———————
            1         5   
Equivalent fraction : The fraction thus generated looks different but has the same value as the whole 
Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator
Adding fractions that have a common denominator :
 3.2       Adding up the two equivalent fractions 
Add the two equivalent fractions which now have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
 x2 + 40x • 5     x2 + 200x
 ————————————  =  —————————
      5               5    
Equation at the end of step 3 :
  (x2 + 200x)    
  ——————————— -  2500
       5         
Step 4 :
Rewriting the whole as an Equivalent Fraction :
 4.1   Subtracting a whole from a fraction 
Rewrite the whole as a fraction using  5  as the denominator :
            2500     2500 • 5
    2500 =  ————  =  ————————
             1          5    
Step 5 :
Pulling out like terms :
 5.1     Pull out like factors :
   x2 + 200x  =   x • (x + 200) 
Adding fractions that have a common denominator :
 5.2       Adding up the two equivalent fractions 
 x • (x+200) - (2500 • 5)     x2 + 200x - 12500
 ————————————————————————  =  —————————————————
            5                         5        
Trying to factor by splitting the middle term
 5.3     Factoring  x2 + 200x - 12500 
 The first term is,  x2  its coefficient is  1 .
The middle term is,  +200x  its coefficient is  200 .
The last term, "the constant", is  -12500 
Step-1 : Multiply the coefficient of the first term by the constant   1 • -12500 = -12500 
Step-2 : Find two factors of  -12500  whose sum equals the coefficient of the middle term, which is   200 .
| -12500 | + | 1 | = | -12499 | ||
| -6250 | + | 2 | = | -6248 | ||
| -3125 | + | 4 | = | -3121 | ||
| -2500 | + | 5 | = | -2495 | ||
| -1250 | + | 10 | = | -1240 | ||
| -625 | + | 20 | = | -605 | ||
| -500 | + | 25 | = | -475 | ||
| -250 | + | 50 | = | -200 | ||
| -125 | + | 100 | = | -25 | ||
| -100 | + | 125 | = | 25 | ||
| -50 | + | 250 | = | 200 | That's it | 
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -50  and  250 
                     x2 - 50x + 250x - 12500
Step-4 : Add up the first 2 terms, pulling out like factors :
                    x • (x-50)
              Add up the last 2 terms, pulling out common factors :
                    250 • (x-50)
 Step-5 : Add up the four terms of step 4 :
                    (x+250)  •  (x+50)
             Which is the desired factorization
Final result :
(x+250) • (x+50)
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