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Solution - Absolute value equations

Exact form: x=-12,32
x=-\frac{1}{2} , \frac{3}{2}
Mixed number form: x=-12,112
x=-\frac{1}{2} , 1\frac{1}{2}
Decimal form: x=0.5,1.5
x=-0.5 , 1.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x3|=|4x|
without the absolute value bars:

|x|=|y||2x3|=|4x|
x=+y(2x3)=(4x)
x=y(2x3)=(4x)
+x=y(2x3)=(4x)
x=y(2x3)=(4x)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x3|=|4x|
x=+y , +x=y(2x3)=(4x)
x=y , x=y(2x3)=(4x)

2. Solve the two equations for x

12 additional steps

(-2x-3)=4x

Subtract from both sides:

(-2x-3)-4x=(4x)-4x

Group like terms:

(-2x-4x)-3=(4x)-4x

Simplify the arithmetic:

-6x-3=(4x)-4x

Simplify the arithmetic:

6x3=0

Add to both sides:

(-6x-3)+3=0+3

Simplify the arithmetic:

6x=0+3

Simplify the arithmetic:

6x=3

Divide both sides by :

(-6x)-6=3-6

Cancel out the negatives:

6x6=3-6

Simplify the fraction:

x=3-6

Move the negative sign from the denominator to the numerator:

x=-36

Find the greatest common factor of the numerator and denominator:

x=(-1·3)(2·3)

Factor out and cancel the greatest common factor:

x=-12

7 additional steps

(-2x-3)=-4x

Add to both sides:

(-2x-3)+3=(-4x)+3

Simplify the arithmetic:

-2x=(-4x)+3

Add to both sides:

(-2x)+4x=((-4x)+3)+4x

Simplify the arithmetic:

2x=((-4x)+3)+4x

Group like terms:

2x=(-4x+4x)+3

Simplify the arithmetic:

2x=3

Divide both sides by :

(2x)2=32

Simplify the fraction:

x=32

3. List the solutions

x=-12,32
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x3|
y=|4x|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.