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Solution - Absolute value equations

Exact form: x=534,598
x=\frac{53}{4} , \frac{59}{8}
Mixed number form: x=1314,738
x=13\frac{1}{4} , 7\frac{3}{8}
Decimal form: x=13.25,7.375
x=13.25 , 7.375

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|6x56||2x3|=0

Add |2x3| to both sides of the equation:

|6x56||2x3|+|2x3|=|2x3|

Simplify the arithmetic

|6x56|=|2x3|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|6x56|=|2x3|
without the absolute value bars:

|x|=|y||6x56|=|2x3|
x=+y(6x56)=(2x3)
x=y(6x56)=((2x3))
+x=y(6x56)=(2x3)
x=y(6x56)=(2x3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||6x56|=|2x3|
x=+y , +x=y(6x56)=(2x3)
x=y , x=y(6x56)=((2x3))

3. Solve the two equations for x

9 additional steps

(6x-56)=(2x-3)

Subtract from both sides:

(6x-56)-2x=(2x-3)-2x

Group like terms:

(6x-2x)-56=(2x-3)-2x

Simplify the arithmetic:

4x-56=(2x-3)-2x

Group like terms:

4x-56=(2x-2x)-3

Simplify the arithmetic:

4x56=3

Add to both sides:

(4x-56)+56=-3+56

Simplify the arithmetic:

4x=3+56

Simplify the arithmetic:

4x=53

Divide both sides by :

(4x)4=534

Simplify the fraction:

x=534

10 additional steps

(6x-56)=-(2x-3)

Expand the parentheses:

(6x-56)=-2x+3

Add to both sides:

(6x-56)+2x=(-2x+3)+2x

Group like terms:

(6x+2x)-56=(-2x+3)+2x

Simplify the arithmetic:

8x-56=(-2x+3)+2x

Group like terms:

8x-56=(-2x+2x)+3

Simplify the arithmetic:

8x56=3

Add to both sides:

(8x-56)+56=3+56

Simplify the arithmetic:

8x=3+56

Simplify the arithmetic:

8x=59

Divide both sides by :

(8x)8=598

Simplify the fraction:

x=598

4. List the solutions

x=534,598
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|6x56|
y=|2x3|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.