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Solution - Absolute value equations

Exact form: x=25
x=25

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x17|=|x33|
without the absolute value bars:

|x|=|y||x17|=|x33|
x=+y(x17)=(x33)
x=y(x17)=(x33)
+x=y(x17)=(x33)
x=y(x17)=(x33)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x17|=|x33|
x=+y , +x=y(x17)=(x33)
x=y , x=y(x17)=(x33)

2. Solve the two equations for x

5 additional steps

(x-17)=(x-33)

Subtract from both sides:

(x-17)-x=(x-33)-x

Group like terms:

(x-x)-17=(x-33)-x

Simplify the arithmetic:

-17=(x-33)-x

Group like terms:

-17=(x-x)-33

Simplify the arithmetic:

17=33

The statement is false:

17=33

The equation is false so it has no solution.

12 additional steps

(x-17)=-(x-33)

Expand the parentheses:

(x-17)=-x+33

Add to both sides:

(x-17)+x=(-x+33)+x

Group like terms:

(x+x)-17=(-x+33)+x

Simplify the arithmetic:

2x-17=(-x+33)+x

Group like terms:

2x-17=(-x+x)+33

Simplify the arithmetic:

2x17=33

Add to both sides:

(2x-17)+17=33+17

Simplify the arithmetic:

2x=33+17

Simplify the arithmetic:

2x=50

Divide both sides by :

(2x)2=502

Simplify the fraction:

x=502

Find the greatest common factor of the numerator and denominator:

x=(25·2)(1·2)

Factor out and cancel the greatest common factor:

x=25

3. Graph

Each line represents the function of one side of the equation:
y=|x17|
y=|x33|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.