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Solution - Simplification or other simple results
19x^2+3x+12
Other Ways to Solve:
Step by Step Solution
Step 1 :
Equation at the end of step 1 :
(19x2 + 12) + 3x
Step 2 :
Trying to factor by splitting the middle term
2.1 Factoring 19x2+3x+12
The first term is, 19x2 its coefficient is 19 .
The middle term is, +3x its coefficient is 3 .
The last term, "the constant", is +12
Step-1 : Multiply the coefficient of the first term by the constant 19 • 12 = 228
Step-2 : Find two factors of 228 whose sum equals the coefficient of the middle term, which is 3 .
-228 | + | -1 | = | -229 | ||
-114 | + | -2 | = | -116 | ||
-76 | + | -3 | = | -79 | ||
-57 | + | -4 | = | -61 | ||
-38 | + | -6 | = | -44 | ||
-19 | + | -12 | = | -31 |
For tidiness, printing of 18 lines which failed to find two such factors, was suppressed
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Final result :
19x2 + 3x + 12
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