Solution - Other Factorizations

Reformatting the input :

Changes made to your input should not affect the solution:

 (1): "x3"   was replaced by   "x^3". 

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                     0-(x^2-12*x^36)=0 

Step by step solution :

Step  1  :

Equation at the end of step  1  :

  0 -  ((x2) -  (22•3x36))  = 0 

Step  2  :

Step  3  :

Pulling out like terms :

 3.1     Pull out like factors :

   -x² + 12x³⁶  =   x² • (12x³⁴ - 1) 

Trying to factor as a Difference of Squares :

 3.2      Factoring:  12x³⁴ - 1 

Theory : A difference of two perfect squares,  A² - B²  can be factored into  (A+B) • (A-B)

Proof :  (A+B) • (A-B) =
         A² - AB + BA - B² =
         A² - AB + AB - B² =
         A² - B²

Note :  AB = BA is the commutative property of multiplication.

Note :  - AB + AB equals zero and is therefore eliminated from the expression.

Check :  12  is not a square !!

Ruling : Binomial can not be factored as the
difference of two perfect squares

Equation at the end of step  3  :

  x2 • (12x34 - 1)  = 0 

Step  4  :

Theory - Roots of a product :

 4.1    A product of several terms equals zero. 

 When a product of two or more terms equals zero, then at least one of the terms must be zero. 

 We shall now solve each term = 0 separately 

 In other words, we are going to solve as many equations as there are terms in the product 

 Any solution of term = 0 solves product = 0 as well.

Solving a Single Variable Equation :

 4.2      Solve  :    x² = 0 

  Solution is  x² = 0

Solving a Single Variable Equation :

 4.3      Solve  :    12x³⁴-1 = 0 

 Add  1  to both sides of the equation : 
                      12x³⁴ = 1
Divide both sides of the equation by 12:
                     x³⁴ = 1/12 = 0.083
                     x  =  34th root of (1/12) 

 The equation has two real solutions  
 These solutions are  x = 34th root of ( 0.083) = ± 0.92952  
 

Three solutions were found :

1.  x = 34th root of ( 0.083) = ± 0.92952
2.  x² = 0