Ufumbuzi - Sifa za mduara

Kipenyo $$\left(d\right)$$ ni sawa na mara mbili za upana:
$$d=2·r$$

$$d=2\cdot r$$

r=0

$$d=2\cdot 0$$

$$d=0$$

Mzunguko $$\left(c\right)$$ ni sawa na mara mbili za upana ukizidisha kwa π:
$$c=2·r·\pi$$

$$c=2\cdot r\cdot \pi$$

r=0

$$c=2\cdot 0\cdot \pi$$

$$c=0\cdot \pi$$

Eneo $$\left(a\right)$$ ni sawa na upana ulio katika mraba ukizidishwa na π:
$$a=r^2·\pi$$

$$a=r^2\cdot \pi$$

r=0

$$a=0^2\cdot \pi$$

$$a=0\cdot \pi$$

Koordineti za kitovu cha duara kawaida, lakini sio mara zote, zinawakilishwa na $$h$$ na $$k$$ katika equation ya aina ya kawaida ya duara:
$${\left(x-h\right)}^2+{\left(y-k\right)}^2=r^2$$
Tambua $$h$$ na $$k$$ katika equation:
$${\left(x-6\right)}^2+{\left(y+-\right)}^2=$$
$$h=6$$
$$k=0$$
Kitovu $$\left(6,0\right)$$

Ili kupata kizuizi cha $$x$$, badilisha $$0$$ kwa $$y$$ katika equation ya aina ya kawaida ya duara
$${\left(x-h\right)}^2+{\left(y-k\right)}^2=r^2$$
na utatue equation ya fiatoni kwa $$x$$:

$${\left(x-6\right)}^2+{\left(y+0\right)}^2=0$$

$${\left(x-6\right)}^2+{\left(0+0\right)}^2=0$$

$${\left(x-6\right)}^2+{\left(-0\right)}^2=0$$

$${\left(x-6\right)}^2+0=0$$

$${\left(x-6\right)}^2=0-0$$

$${\left(x-6\right)}^2=0$$

$$\sqrt{\left({\left(x-6\right)}^2\right)}=\sqrt{\left(0\right)}$$

$$x-6=\sqrt{\left(0\right)}$$

$$x=\pm \sqrt{\left(0\right)}+6$$

$$x=\pm 0+6$$

$$x=\left(6,0\right)$$

Kupata kuingilia kwa $$y$$, chukua $$0$$ kwa $$x$$ katika mahesabu ya mfumo wa kawaida wa duara
$${\left(x-h\right)}^2+{\left(y-k\right)}^2=r^2$$
na suluhisha mahesabu ya quadratic kwa $$y$$:

$${\left(x-6\right)}^2+{\left(y+0\right)}^2=0$$

$${\left(0-6\right)}^2+{\left(y+0\right)}^2=0$$

$${\left(-6\right)}^2+{\left(y+0\right)}^2=0$$

$$36+{\left(y+0\right)}^2=0$$

$${\left(y+0\right)}^2=0-36$$

$${\left(y+0\right)}^2=-36$$

$$\sqrt{\left({\left(y+0\right)}^2\right)}=\sqrt{\left(-36\right)}$$

$$y+0=\sqrt{\left(-36\right)}$$

$$y=\pm \sqrt{\left(-36\right)}-0$$

Hakuna kuingilia kwa y

CircleFromEquationSolverStep7TextUnit1