పరిష్కారం - జ్యామితీ నిర్ణయాలు

శ్రేణికి సామాన్య రూపాన్ని కనుగొనడానికి, మొదటి పదాన్ని: $$a=198$$ మరియు పునరావృత్తి అనుపాతాన్ని: $$r=1.9444444444444444$$ జామితీయ శ్రేణుల సూత్రానికి ప్లగ్ చేయండి:

$$a_1=198$$

$$a_2=a_1·r^{n-1}=198\cdot {1.9444444444444444}^{2-1}=198\cdot {1.9444444444444444}^1=198\cdot 1.9444444444444444=385$$

$$a_3=a_1·r^{n-1}=198\cdot {1.9444444444444444}^{3-1}=198\cdot {1.9444444444444444}^2=198\cdot 3.780864197530864=748.6111111111111$$

$$a_4=a_1·r^{n-1}=198\cdot {1.9444444444444444}^{4-1}=198\cdot {1.9444444444444444}^3=198\cdot 7.351680384087791=1455.6327160493827$$

$$a_5=a_1·r^{n-1}=198\cdot {1.9444444444444444}^{5-1}=198\cdot {1.9444444444444444}^4=198\cdot 14.294934080170705=2830.3969478737995$$

$$a_6=a_1·r^{n-1}=198\cdot {1.9444444444444444}^{6-1}=198\cdot {1.9444444444444444}^5=198\cdot 27.795705155887482=5503.549620865721$$

$$a_7=a_1·r^{n-1}=198\cdot {1.9444444444444444}^{7-1}=198\cdot {1.9444444444444444}^6=198\cdot 54.047204469781214=10701.34648501668$$

$$a_8=a_1·r^{n-1}=198\cdot {1.9444444444444444}^{8-1}=198\cdot {1.9444444444444444}^7=198\cdot 105.09178646901903=20808.17372086577$$

$$a_9=a_1·r^{n-1}=198\cdot {1.9444444444444444}^{9-1}=198\cdot {1.9444444444444444}^8=198\cdot 204.34514035642587=40460.337790572325$$

$$a_{10}=a_1·r^{n-1}=198\cdot {1.9444444444444444}^{10-1}=198\cdot {1.9444444444444444}^9=198\cdot 397.3377729152725=78672.87903722396$$