పరిష్కారం - జ్యామితీ నిర్ణయాలు

శ్రేణికి సామాన్య రూపాన్ని కనుగొనడానికి, మొదటి పదాన్ని: $$a=37$$ మరియు పునరావృత్తి అనుపాతాన్ని: $$r=0.02702702702702703$$ జామితీయ శ్రేణుల సూత్రానికి ప్లగ్ చేయండి:

$$a_1=37$$

$$a_2=a_1·r^{n-1}=37\cdot {0.02702702702702703}^{2-1}=37\cdot {0.02702702702702703}^1=37\cdot 0.02702702702702703=1$$

$$a_3=a_1·r^{n-1}=37\cdot {0.02702702702702703}^{3-1}=37\cdot {0.02702702702702703}^2=37\cdot 0.0007304601899196495=0.027027027027027032$$

$$a_4=a_1·r^{n-1}=37\cdot {0.02702702702702703}^{4-1}=37\cdot {0.02702702702702703}^3=37\cdot 1.974216729512566E-05=0.0007304601899196495$$

$$a_5=a_1·r^{n-1}=37\cdot {0.02702702702702703}^{5-1}=37\cdot {0.02702702702702703}^4=37\cdot 5.335720890574504E-07=1.9742167295125664E-05$$

$$a_6=a_1·r^{n-1}=37\cdot {0.02702702702702703}^{6-1}=37\cdot {0.02702702702702703}^5=37\cdot 1.4420867271822984E-08=5.335720890574504E-07$$

$$a_7=a_1·r^{n-1}=37\cdot {0.02702702702702703}^{7-1}=37\cdot {0.02702702702702703}^6=37\cdot 3.897531695087293E-10=1.4420867271822984E-08$$

$$a_8=a_1·r^{n-1}=37\cdot {0.02702702702702703}^{8-1}=37\cdot {0.02702702702702703}^7=37\cdot 1.0533869446181874E-11=3.8975316950872935E-10$$

$$a_9=a_1·r^{n-1}=37\cdot {0.02702702702702703}^{9-1}=37\cdot {0.02702702702702703}^8=37\cdot 2.846991742211317E-13=1.0533869446181874E-11$$

$$a_{10}=a_1·r^{n-1}=37\cdot {0.02702702702702703}^{10-1}=37\cdot {0.02702702702702703}^9=37\cdot 7.694572276246804E-15=2.846991742211317E-13$$