పరిష్కారం - జ్యామితీ నిర్ణయాలు

శ్రేణికి సామాన్య రూపాన్ని కనుగొనడానికి, మొదటి పదాన్ని: $$a=495$$ మరియు పునరావృత్తి అనుపాతాన్ని: $$r=0.01616161616161616$$ జామితీయ శ్రేణుల సూత్రానికి ప్లగ్ చేయండి:

$$a_1=495$$

$$a_2=a_1·r^{n-1}=495\cdot {0.01616161616161616}^{2-1}=495\cdot {0.01616161616161616}^1=495\cdot 0.01616161616161616=8$$

$$a_3=a_1·r^{n-1}=495\cdot {0.01616161616161616}^{3-1}=495\cdot {0.01616161616161616}^2=495\cdot 0.0002611978369554127=0.1292929292929293$$

$$a_4=a_1·r^{n-1}=495\cdot {0.01616161616161616}^{4-1}=495\cdot {0.01616161616161616}^3=495\cdot 4.221379183117781E-06=0.0020895826956433016$$

$$a_5=a_1·r^{n-1}=495\cdot {0.01616161616161616}^{5-1}=495\cdot {0.01616161616161616}^4=495\cdot 6.822431003018636E-08=3.377103346494225E-05$$

$$a_6=a_1·r^{n-1}=495\cdot {0.01616161616161616}^{6-1}=495\cdot {0.01616161616161616}^5=495\cdot 1.1026151115989716E-09=5.457944802414909E-07$$

$$a_7=a_1·r^{n-1}=495\cdot {0.01616161616161616}^{7-1}=495\cdot {0.01616161616161616}^6=495\cdot 1.7820042207660146E-11=8.820920892791772E-09$$

$$a_8=a_1·r^{n-1}=495\cdot {0.01616161616161616}^{8-1}=495\cdot {0.01616161616161616}^7=495\cdot 2.8800068214400233E-13=1.4256033766128114E-10$$

$$a_9=a_1·r^{n-1}=495\cdot {0.01616161616161616}^{9-1}=495\cdot {0.01616161616161616}^8=495\cdot 4.6545564790949875E-15=2.3040054571520186E-12$$

$$a_{10}=a_1·r^{n-1}=495\cdot {0.01616161616161616}^{10-1}=495\cdot {0.01616161616161616}^9=495\cdot 7.522515521769677E-17=3.72364518327599E-14$$